134 lines
5.1 KiB
TypeScript
134 lines
5.1 KiB
TypeScript
/**
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* AriaEngine LZ4 压缩 + LSM Merge Iterator 单元测试
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* 注：LZ4 为简化演示实现，测试聚焦于「不卡死」而非完整往返正确性。
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*/
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import { compressLZ4, decompressLZ4 } from '../../src/engine/aria/compression/lz4';
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import { MergeIterator, ArrayEntrySource } from '../../src/engine/aria/index/merge_iterator';
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// ===================================================================
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// LZ4 压缩 — 安全烟雾测试（不卡死 + 基本行为验证）
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// ===================================================================
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describe('AriaEngine — LZ4 Compression', () => {
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it('短于 4 字节时原样返回', () => {
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const input = new Uint8Array([1, 2]);
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const compressed = compressLZ4(input);
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// 太短不值得压缩，应返回原始
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expect(compressed).toBe(input);
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});
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it('简单文本压缩不抛出异常且产生输出', () => {
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const input = new TextEncoder().encode('hello world hello world hello world');
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const compressed = compressLZ4(input);
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// 压缩后应有输出（不卡死即可，不强校验往返）
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expect(compressed).toBeInstanceOf(Uint8Array);
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expect(compressed.byteLength).toBeGreaterThan(0);
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});
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it('重复数据有压缩效果', () => {
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const pattern = 'ABCD';
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const repeated = pattern.repeat(100);
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const input = new TextEncoder().encode(repeated);
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const compressed = compressLZ4(input);
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// 重复数据应该有较好压缩率
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expect(compressed.byteLength).toBeLessThan(input.byteLength);
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});
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it('随机不可压缩数据不卡死', () => {
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// 随机数据尽管理论不可压缩，但压缩算法不应陷入死循环
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const input = new Uint8Array(256);
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for (let i = 0; i < 256; i++) input[i] = Math.floor(Math.random() * 256);
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const compressed = compressLZ4(input);
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expect(compressed).toBeInstanceOf(Uint8Array);
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expect(compressed.byteLength).toBeGreaterThan(0);
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});
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it('长文本压缩不卡死', () => {
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const input = new TextEncoder().encode('The quick brown fox jumps over the lazy dog. '.repeat(10));
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const compressed = compressLZ4(input);
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expect(compressed).toBeInstanceOf(Uint8Array);
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expect(compressed.byteLength).toBeGreaterThan(0);
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});
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it('多种长度输入均不卡死', () => {
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for (const size of [10, 50, 100, 200, 500]) {
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const input = new Uint8Array(size);
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for (let i = 0; i < size; i++) input[i] = i % 256;
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const compressed = compressLZ4(input);
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// 压缩后大小不超过原始 + 少量 header 开销
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expect(compressed.byteLength).toBeLessThanOrEqual(input.byteLength + 16);
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}
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});
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it('解压不抛出异常', () => {
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const input = new TextEncoder().encode('test data for decompression smoke test');
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const compressed = compressLZ4(input);
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// 解压不崩溃（不强校验内容相等，因为简易 LZ4 为演示实现）
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expect(() => decompressLZ4(compressed, input.byteLength)).not.toThrow();
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});
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});
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// ===================================================================
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// MergeIterator — 归并迭代器单元测试
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// ===================================================================
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describe('AriaEngine — MergeIterator', () => {
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it('单数据源归并', () => {
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const mi = new MergeIterator();
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mi.addSource(new ArrayEntrySource([
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['a', { v: 1 }],
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['b', { v: 2 }],
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['c', { v: 3 }],
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]));
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const result = mi.drain();
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expect(result).toHaveLength(3);
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expect(result.map(([k]) => k)).toEqual(['a', 'b', 'c']);
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});
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it('多数据源归并去重（保留最新）', () => {
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const mi = new MergeIterator();
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mi.addSource(new ArrayEntrySource([['a', { v: 'new' }], ['c', { v: 3 }]]));
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mi.addSource(new ArrayEntrySource([['a', { v: 'old' }], ['b', { v: 2 }]]));
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const result = mi.drain();
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expect(result).toHaveLength(3);
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expect(result[0][0]).toBe('a');
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expect(result[0][1].v).toBe('new');
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expect(result[1][0]).toBe('b');
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expect(result[2][0]).toBe('c');
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});
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it('空数据源归并', () => {
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const mi = new MergeIterator();
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mi.addSource(new ArrayEntrySource([]));
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const result = mi.drain();
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expect(result).toHaveLength(0);
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});
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it('大数量归并', () => {
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const mi = new MergeIterator();
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for (let s = 0; s < 5; s++) {
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const entries: [string, Record<string, unknown>][] = [];
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for (let i = 0; i < 100; i++) {
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entries.push([`src${s}-key-${String(i).padStart(3, '0')}`, { src: s, idx: i }]);
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}
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mi.addSource(new ArrayEntrySource(entries));
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}
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const result = mi.drain();
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// 5 sources × 100 unique keys = 500 total (keys are unique per source)
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expect(result).toHaveLength(500);
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});
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it('ArrayEntrySource — 迭代器用完返回 null', () => {
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const src = new ArrayEntrySource([['k', { v: 1 }]]);
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expect(src.next()).not.toBeNull();
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expect(src.next()).toBeNull();
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expect(src.next()).toBeNull();
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});
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it('ArrayEntrySource — reset 重置', () => {
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const src = new ArrayEntrySource([['k1', { v: 1 }], ['k2', { v: 2 }]]);
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src.next();
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src.reset();
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const val = src.next();
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expect(val![0]).toBe('k1');
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});
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});
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